Question

PROVE: Log (base b) a × Log (base c) b × Log (base d) c = Log (base d) a

Answer 1

Answer:

solved

Step-by-step explanation:

PROVE: Log (base b) a × Log (base c) b × Log (base d) c = Log (base d) a

LHS =  Log (base b) a × Log (base c) b × Log (base d) c

= Log  a /logb x logb/logc x logc/logd

= loga/logb

= Log (base d) a

= RHS