Question

Prove: loga^x=loga^e.loge^x

Answer 1

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(M)log, start base, b, end base, left parenthesis, M, start superscript, p, end superscript, right parenthesis, equals, p, log, start base, b, end base, left parenthesis, M, right parenthesis

This time, only MMM is involved in the property and so it is sufficient to let M=b^xM=b

x

M, equals, b, start superscript, x, end superscript, which gives us that \log_b(M)=xlog

b

(M)=xlog, start base, b, end base, left parenthesis, M, right parenthesis, equals, x.