Question

Prove: No number of the 4m+2 is a perfect square

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

tried to prove this by proof by contradiction: if n is a perfect square, then its square root, say x, is an integer. Suppose n is of the form 4k+3. Then

x2=4k+3

which we can also write as

x2≡3mod4

However, this congruence has no solutions. Therefore our initial assumption that n is of the form 4k+3 was false and n cannot be of the form 4k+3.

I know there's something missing or wrong in this proof but I don't know what. Any help would be appreciated.

Step-by-step explanation:

hope this will help