Question

Prove of Pythagoras

Answer 1

Here is your answer.

Answer 2

Answer:

Answer:Hey mate i will help u

Answer:Hey mate i will help u Given: XYZ is a rt. angled triangle with <Y a right angle and its hypotenuse (XZ) is "a", height (XY) is "b" and base (YZ) is "c"

Answer:Hey mate i will help u Given: XYZ is a rt. angled triangle with <Y a right angle and its hypotenuse (XZ) is "a", height (XY) is "b" and base (YZ) is "c" To prove: a² = b² + c²

Answer:Hey mate i will help u Given: XYZ is a rt. angled triangle with <Y a right angle and its hypotenuse (XZ) is "a", height (XY) is "b" and base (YZ) is "c" To prove: a² = b² + c² Construction: A square PQRS is constructed with all its sides equal to (b+c). Inside it, a tilted square EFGH is drawn whose all sides are equal to 'a'.

Answer:Hey mate i will help u Given: XYZ is a rt. angled triangle with <Y a right angle and its hypotenuse (XZ) is "a", height (XY) is "b" and base (YZ) is "c" To prove: a² = b² + c² Construction: A square PQRS is constructed with all its sides equal to (b+c). Inside it, a tilted square EFGH is drawn whose all sides are equal to 'a'. Proof:

Area of square EFGH = a²

Area of square EFGH = a²Area of all four right angled triangles formed = 4 × 1/2 × b × c = 2 bc

Area of square EFGH = a²Area of all four right angled triangles formed = 4 × 1/2 × b × c = 2 bcArea of square PQRS = (b+c)²

Area of square EFGH = a²Area of all four right angled triangles formed = 4 × 1/2 × b × c = 2 bcArea of square PQRS = (b+c)²Area of square PQRS = Area of square EFGH + Area of four rt. angled triangles

Area of square EFGH = a²Area of all four right angled triangles formed = 4 × 1/2 × b × c = 2 bcArea of square PQRS = (b+c)²Area of square PQRS = Area of square EFGH + Area of four rt. angled triangles= a² + 2 bc

Area of square EFGH = a²Area of all four right angled triangles formed = 4 × 1/2 × b × c = 2 bcArea of square PQRS = (b+c)²Area of square PQRS = Area of square EFGH + Area of four rt. angled triangles= a² + 2 bcBy condition,

Area of square EFGH = a²Area of all four right angled triangles formed = 4 × 1/2 × b × c = 2 bcArea of square PQRS = (b+c)²Area of square PQRS = Area of square EFGH + Area of four rt. angled triangles= a² + 2 bcBy condition,(b+c)² = a² + 2bc

Area of square EFGH = a²Area of all four right angled triangles formed = 4 × 1/2 × b × c = 2 bcArea of square PQRS = (b+c)²Area of square PQRS = Area of square EFGH + Area of four rt. angled triangles= a² + 2 bcBy condition,(b+c)² = a² + 2bcOr, b²+2bc+c² = a²+2bc

Area of square EFGH = a²Area of all four right angled triangles formed = 4 × 1/2 × b × c = 2 bcArea of square PQRS = (b+c)²Area of square PQRS = Area of square EFGH + Area of four rt. angled triangles= a² + 2 bcBy condition,(b+c)² = a² + 2bcOr, b²+2bc+c² = a²+2bcOr, a² = b²+c²

(Hence prove.)

This will help u