Math, asked by tikendrajitsaikia112, 7 hours ago

Prove or disprove: Every PID is UFD.​

Answers

Answered by sampadasur
1

Z[x] is not a PID (e.g. the set of polynomials in Z[x] whose constant term is even is a non-principal ideal) but Z[x] is a UFD. To see this note that irreducible elements in Z[x] are either integers of the form ±p for a prime p, or primitive irreducible polynomials of degree ≥ 1.

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