Question

The digit in the tens place of a two-digit number is 6
more than the digit in the units place. Let the digit at
units place be b. Then the number is:​

Answer 1

Answer:

11b+60

Step-by-step explanation:

Let's make the question easy for us to understand.

We have a two-digit number. The tens place of this number is 6 more than the digit in the unit's place.

Let's assume the unit's place as 'b' as said in the question.

When the question says that the tens place is 6 more than the digit in unit place, what does that literally suggest? It is, the ten's place is 6 + unit's place(6 + b).

Also, it is mentioned that the given number is a two-digit number. So, for that, we know that the number would be -> 10(ten’s place) + unit’s place

=> 10(b+6) + b

=>  11b+60

Answer 2

Step-by-step explanation:

let unit place digit = b

according to question

tens place digit = 6 + b

we have two digit number = 10× (6+b) +b

= 60 +11b