prove positive integer and its square sum is always even
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Answered by
1
Step-by-step explanation:
Let the positive integer be 1
Square of 1 is 1 and sum of it is always even that is 2
Answered by
3
Step-by-step explanation:
let the integer be 2n+1
ATP
(2n+1)+(2n+1)²
=2n+1+4n²+4n+1
=4n²+6n+2
=2(2n²+3n+1)
Thus the aquired equation is divisible by 2 and hence we can say its an even number ...
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