Question

prove pythagorous theorem

Answer 1

Answer:

Step-by-step explanation:

ABC is a right angle triangle at B and BD is a perpendicular from B on to AC, the diagonal.

Triangles ABC and BDC are similar, as:

    . angle DBC = 90 - angle C = angle A

    . angle ABC = angle BDC = 90

Ratios of corresponding sides are equal.

    AB / BD = BC / DC = AC / BC

   So we get  BC² = AC * DC     --- (1)

Triangle ABC and ADB are similar, as:

   . angle DBA = 90 - (90 - C) = angle C

   . angle ABC = 90 = angle ADB

so ratios of corresponding sides are equal

        AB / AD = BC / BD = AC / AB

      So we get  AB² = AD * AC  --- (2)

 Add (1) and (2) to get:

      AB² + BC² = AC * ( AD + DC) = AC * AC = AC²

Answer 2

Answer:

Step-by-step explanation: