Question

prove rhs=llhs for above question​

Answer 1

Answer:

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Answer 2

Answer:

$RHS = tan\theta + cot\theta \\= \sqrt{(tan\theta+cot\:theta)^{2}}\\= \sqrt{ tan^{2}\theta + 2 tan\:theta cot \:theta + cot^{2}\theta }\\= \sqrt{ tan^{2}\theta + 2\times 1 + cot^{2}\theta }$

$\boxed { \pink { tan\theta cot\theta = 1 }}$

$= \sqrt{ tan^{2}\theta + 2+ cot^{2}\theta }$

$= \sqrt{(1+ tan^{2}\theta )+(1 + cot^{2}\theta) }$

$= \sqrt{ sec^{2}\theta + cosec^{2}\theta }$

$\boxed { \blue { 1+ tan^{2}\theta = sec^{2}\theta }}$

$\boxed { \orange { 1+ cot^{2}\theta = cosec^{2}\theta }}$

$= LHS$

$Hence , proved$

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