Question

prove root 2 is irrational?​

Answer 1

Hey mate!

Here is your answer...

Hope this helps :)

Answer 2

Here is your answer ⤵⤵⤵

Let √2 be a rational number

√2 = a/b (where a and b are coprime integers and b is not equal to 0)

squaring both sides

2 = a²/b²

=> 2b² = a²

a² is divisible by 2

=> a is divisible by 2

a = 2c

squaring both sides

a² = (2c)²

=> a² = 4c²

also, a² = 2b²

=> 2b² = 4c²

=> b² = 2c²

b² is divisible by 2

=> b is divisible by 2

which is a contradiction as a and b are co prime integers.

Our assumption is wrong.

√2 is an irrational number.

Hence Proved

HOPE IT HELPS YOU ☺☺!!!