Question

prove
sin (A -45°) =1/√2(sin A -cos A)
​

Answer 1

Step-by-step explanation:

$sin(A-45°)=sinAcos45°-cosAsin45°</p><p> \\ = sinA \frac{1}{ \sqrt{2} } -cosA \frac{1}{ \sqrt{2} } \\ = \frac{1}{ \sqrt{2} } (sinA-cosA)\\sin(A-B)=sinAcosB-cosAsinB it's formula$