prove sin theta/ theta =1
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Answer:
sin∅ /sin∅ = 1
as numerator and denominator both area same then answer will be 1
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Hence it is proved that lim (x -> 0) sin theta/ theta = 1
sin theta/ theta ≠ 1
instead
lim (x -> 0) sin theta/ theta = 1
Expansion of sin theta is given by,
sin theta = theta - theta^3/3! + theta^5/5! - ..........
dividing both sides by theta, we get,
sin theta / theta = 1 - theta^2/3! + theta^4/5! - ..........
upon applying the lim (x -> 0) on both sides, we get,
lim (x -> 0) sin theta / theta = lim (x -> 0) (1 - theta^2/3! + theta^4/5! - ..........)
lim (x -> 0) sin theta / theta = 1 - 0 + 0 - ............... (as lim (x -> 0) 1 = 1)
∴ lim (x -> 0) sin theta / theta = 1
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