Question

prove thant √3 is an irrational number​

Answer 1

Step-by-step explanation:

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sunil ⬅️

Answer 2

Step-by-step explanation:

let √3 is rational

√3=a/b (where a and b are co-prime and a= not0)

√3b=a

by squring both side

3b^2=a^2

[3 divides a^2]

[so, 3 also divides a]

let a^2=3 c^2

3b^2=9c^2

b^2=3c^2

[3 divides b^2]

[so,3 also divides b]

but we assume that a and b are co-prime

this contradiction is arisen because of our wrong assumption

threfore, √3 is an irrational Number

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