Question

prove that 1+1+1=7.

.....crt ans ll be marked as brainliest. ☺

Answer 1

Heya user,

Assume a=b,
=> a² = ab
=> a² - b² = ab - b²
=> (a+b)(a-b) = b(a-b)
=> a+b = b
=> 2b = b or 2=1;

Now, we know, (-1) = (-1)³
Taking logarithms, 1 * log(-1) = 3 * log(-1)
=> 1= 3;

Now, 1=2 and 1=3 => (1+1) + 1 = (2+2) + 3 = 7

And Hence, 1 + 1 + 1 = 7; ☺

Answer 2

Step-by-step explanation:

Heya user,

Assume a=b,

=> a² = ab

=> a² - b² = ab - b²

=> (a+b)(a-b) = b(a-b)

=> a+b = b

=> 2b = b or 2=1;

Now, we know, (-1) = (-1)³

Taking logarithms, 1 * log(-1) = 3 * log(-1)

=> 1= 3;

Now, 1=2 and 1=3 => (1+1) + 1 = (2+2) + 3 = 7

And Hence, 1 + 1 + 1 = 7; ☺