prove that 1+2+3+4+5+infinity=-1/2.....plzzz guys help me......it is vry important...
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Let S = 1+2+3+4+5+6+7
Consider S1= 1-1+1-1+1-1+1-1…..
S1=1-1+1-1+1-1+1…..
1-S1=1-(1-1+1-1+1-1+1…)
1-S1=1-1+1-1+1-1+1…..
1-S1=S1
So, S1=1/2
Let S2=1-2+3-4+5-6+7…..
So, S2=1-2+3-4+5-6+7-8+9…..
S2= 1-2+3-4+5-6+7-8……. I have shifted RHS by a unit position
+ 2S2=1-1+1-1+1-1+1…..
Hence, 2S2=S1
Therefore, S2=1/4
Let’s come back to our sum of infinite numbers.
S=1+2+3+4+5+6+7+8+9…..
S2=1-2+3-4+5-6+7-8+9….
So, S-S2=4+8+12+16+20…..
Hence, S-S2=4(1+2+3+4+5+6+7+8….)
S-S2=4S
So, -S2=3S
And, S=-S2/3=-1/12
Hope it helps
Pls don't raise objection
I know there are objections.
But I don't have the answer to those objections
U wanted the proof so uploaded it
Consider S1= 1-1+1-1+1-1+1-1…..
S1=1-1+1-1+1-1+1…..
1-S1=1-(1-1+1-1+1-1+1…)
1-S1=1-1+1-1+1-1+1…..
1-S1=S1
So, S1=1/2
Let S2=1-2+3-4+5-6+7…..
So, S2=1-2+3-4+5-6+7-8+9…..
S2= 1-2+3-4+5-6+7-8……. I have shifted RHS by a unit position
+ 2S2=1-1+1-1+1-1+1…..
Hence, 2S2=S1
Therefore, S2=1/4
Let’s come back to our sum of infinite numbers.
S=1+2+3+4+5+6+7+8+9…..
S2=1-2+3-4+5-6+7-8+9….
So, S-S2=4+8+12+16+20…..
Hence, S-S2=4(1+2+3+4+5+6+7+8….)
S-S2=4S
So, -S2=3S
And, S=-S2/3=-1/12
Hope it helps
Pls don't raise objection
I know there are objections.
But I don't have the answer to those objections
U wanted the proof so uploaded it
Anonymous:
Dont worry
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