Math, asked by janvi47, 1 year ago

Prove that 1 + √2 is irrational.​

Answers

Answered by JoyDubey
16

Step-by-step explanation:

Sol:

→ If possible let 1 + √2 is rational number.

→ 1 + √2 - 1 is also a rational number.

→ but √2 is irrational

★ Our contradiction arises by assuming 1 + √2 rational, that is wrong...

so, 1 + √2 is irrational number.

#hoPe #iT #heLps #yOu..

Answered by Anonymous
5

\mathfrak{\underline{\underline{\green{Solution:-}}}}

To Prove:

\mathsf{ 1+\sqrt{2} \: \:  is\: irrational }

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Proof:

Let us assume, \</strong><strong>mathsf{</strong><strong>1</strong><strong>+</strong><strong> </strong><strong>\</strong><strong>sqrt{</strong><strong>2</strong><strong>}</strong><strong> </strong><strong>\</strong><strong>:</strong><strong>\</strong><strong>:</strong><strong> </strong><strong>is </strong><strong>\</strong><strong>:</strong><strong> </strong><strong>rational</strong><strong>}</strong><strong>

\\

Therefore

\mathsf{ 1+\sqrt{2} = \dfrac{a}{b} \:\:\:\: (a,b \: are \: integers)}

\mathsf{\sqrt{2}= \dfrac{a}{b}-1}

\mathsf{\sqrt{2}= \dfrac{a-b}{b}}

\\

Here,

RHS is rational

But, LHS is irrational

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A rational and irrational are never equal!

So, our assumption is False

Therefore, \mathsf{ 1+\sqrt{2}} is irrational

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HENCE PROVED!


janvi47: xD
janvi47: super bro
Anonymous: thanks bro
JoyDubey: Thanks for answering...
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