Question

prove that 1/2 - root 3/5 is irrational

wrong will reported​

Answer 1

Answer:

correct answer aahe

I hope answer is correct

Answer 2

Answer:

$= \frac{1}{2} - \frac{ \sqrt{3} }{5}$

$= \frac{5 - 2 \sqrt{3} }{6}$

$let \: \frac{5 - 2 \sqrt{3} }{6} be \: a \: rational \: number$

$\: in \: form \: of \: \frac{p}{q}$

$\: \: \: = \frac{5 - 2 \sqrt{3} }{6} = \frac{p}{q}$

$= 5 - 2 \sqrt{3 \: \: = } 6 \frac {p}{q}$

$2 \sqrt{3 \: } = 5 - 6 \frac{p}{q}$

$= 2 \sqrt{3} = \frac{5q - 6p}{q}$

$\sqrt{3 } = \: \frac{5q - 6p}{2q}$

$thus \: \sqrt{5 } \: is \: the \: rational \: number$

$due \: to \: \frac{5q - 6p}{2q}$

$this \: condradicts \sqrt{3} \: is \: irrational$

Therefore 1/2 - root 3/5 is irrational