prove that 1/ 2 Sin 10°- ROOT 3/ 2 Cos 10°= 2
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Answer:
LHS :
sin10
o
1
−
cos10
o
3
=2[
2sin10
o
1
−
2cos10
o
3
]
=2[
sin10
o
sin30
o
−
cos10
o
cos30
o
]
=2[
sin10
o
cos10
o
sin30
o
cos10
o
−cos30
o
sin10
o
]
=2[
sin10
o
cos10
o
sin20
o
]
=2×2[
sin10
o
cos10
o
sin10
o
cos10
o
]
=4 = RHS
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