Question

prove that 1/3-√5 be a irrational number​

Answer 1

We know √5 is irrational

let root 1/3 - √5 be of the form p/q where p and q are co prime and q is not equal to zero

1/3 - √5 = p/q

√5 = p/q - 1/3

√5 = 1/3 - p/q

√5 = q - 3p / 3q

√5 = q - 3p/ 6q

Hence, √5 should be rational from the above eqn.

But we know that √5 is irrational

So, our assumption is incorrect

1/3 - √5 is irrational

Answer 2

Answer:

we know that

$2 \sqrt{5}$

Step-by-step explanation:

is irrational number

let 1/2-2

$2 \sqrt{5}$

is irrational number