Prove that 1/(4-sec^2〖2π/7〗 )+1/(4-sec^2〖4π/7〗 )+1/(4-sec^2〖6π/7〗 )=1
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Answer:
I tried doing this way:
Look at y=cosθ+isinθ where θ∈{2π7,4π7,⋯,2π}
Then we have
y7y7−1(y−1)⋅(y6+y5+⋯+1)=1=0=0
Now the root y=1 corresponds to θ=2π, and that
y6+y5+⋯+1=0
have roots cosθ+isinθ, where θ∈{2π7,4π7,⋯}. Looking at y+1y will give me the roots as cosθ and then i can put z=y2 to get cos2 as the roots and the invert to get sec2, but I have some problems.
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