Math, asked by shivappam2011, 5 months ago

prove that 1 ÷√9-√8_1√8÷√7+1√7-√6_1√6-√5+1√5-√4= 5​

Answers

Answered by abhinavranjan3434
1

Answer:

1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2=5

Now,

1/3-√8 = 3+√8,

1/√8-√7 = √8+√7,

1/√7-√6 = √7+√6,

1/√6-√5 = √6+√5,

1/√5-2 = √5+2

∴ 1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2

= 3+√8-√8-√7+√7+√6-√6-√5+√5+2

=3+2 = 5

Hence proved.

Step-by-step explanation:

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