prove that 1 ÷√9-√8_1√8÷√7+1√7-√6_1√6-√5+1√5-√4= 5
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Answer:
1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2=5
Now,
1/3-√8 = 3+√8,
1/√8-√7 = √8+√7,
1/√7-√6 = √7+√6,
1/√6-√5 = √6+√5,
1/√5-2 = √5+2
∴ 1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2
= 3+√8-√8-√7+√7+√6-√6-√5+√5+2
=3+2 = 5
Hence proved.
Step-by-step explanation:
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