Question

Prove that 1- cos A /1+ cos A=(cosec A-coA) 2

Answer 1

[tex] \frac{1-cos A}{1+cos A}\\ = \frac{(1-cos A)(1-cos A)}{(1+ cosA)(1-cos A)} \\= \frac{(1-cos A)^2}{1-cos^2A} [/tex]
$\frac{(1-cos A)^2}{sin^2A} = [\frac{1-cos A}{sin A} ]^2=(cosec A-cot A)^2$

Answer 2

Answer:

Step-by-step explanation: