Prove that 1- cos A /1+ cos A=(cosec A-coA) 2
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[tex] \frac{1-cos A}{1+cos A}\\ = \frac{(1-cos A)(1-cos A)}{(1+ cosA)(1-cos A)}
\\= \frac{(1-cos A)^2}{1-cos^2A} [/tex]
![\frac{(1-cos A)^2}{sin^2A} = [\frac{1-cos A}{sin A} ]^2=(cosec A-cot A)^2](https://tex.z-dn.net/?f=+%5Cfrac%7B%281-cos+A%29%5E2%7D%7Bsin%5E2A%7D+%3D+%5B%5Cfrac%7B1-cos+A%7D%7Bsin+A%7D+%5D%5E2%3D%28cosec+A-cot+A%29%5E2 "\frac{(1-cos A)^2}{sin^2A} = [\frac{1-cos A}{sin A} ]^2=(cosec A-cot A)^2")
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