Question

prove that 1-cos2ø : sin2Ø =tan Ø​

Answer 1

Step-by-step explanation:

According to question,

1+cos2θ+sin2θ

1−cos2θ+sin2θ

=tanθ

Solving LHS,

⟹

2cos

2

θ+ 2sinθ.cosθ

2sin

2

θ+2cosθsinθ

⟹

2cosθ(sinθ+cosθ)

2sinθ(cosθ+sinθ)

⟹

cosθ

sinθ

⟹tanθ=RHS

Hence proved