Prove that 1+cosA / 1-cosA = (cosec A + cot A)^2
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Answer:
(1-cosA)/(1+cosA)
=(1-cosA)/(1+cosA) ×(1-cosA)/(1-cosA)
=(1-cosA)^2 /(1-cos^2A)
=(1-cosA)^2 / (sin^2A)
=(1/sinA - cosA/sinA )^2
=cosecA - cotA)^2
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