Prove that:
(1+cosA+tanA) (sinA-cosA)=sinA tanA-cotA cosA
Answers
Answered by
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sorry to tell you but you have incorrectly written cosA in place of cotA.
[ 1+ cotA+ tanA ] [ sinA - cosA]
LHS
= sinA + sinAcotA + sinAtanA - cosA - cosAcotA - tanAcosA
= sinA + sinA * cosA/sinA + sinAtanA - cosA - cosAcotA - cosA * sinA/cosA
= sinA + cosA + sinAtanA - cosA - cosAcotA - sinA
= sinAtanA - cosAcotA
= RHS
LHS = RHS
hence proved and hope this helps..
[ 1+ cotA+ tanA ] [ sinA - cosA]
LHS
= sinA + sinAcotA + sinAtanA - cosA - cosAcotA - tanAcosA
= sinA + sinA * cosA/sinA + sinAtanA - cosA - cosAcotA - cosA * sinA/cosA
= sinA + cosA + sinAtanA - cosA - cosAcotA - sinA
= sinAtanA - cosAcotA
= RHS
LHS = RHS
hence proved and hope this helps..
Parthika:
No but there is cosA
then it'snot possible
Ok
Thanks
or there might be some prinitng mistake
yaa no problem
Yes
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