Prove that :-
1/cosec theta-cot theta - 1/sin theta = 1/sin theta - 1/cosec theta+cot theta
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Hey mate......
here's the answer.....
Given, 1/cosec theta + cot theta - 1/sin theta
It can be written as,
= 1/cosec theta + cot theta * cosec theta - cot theta/cosec theta - cot theta - 1/sin theta
= cosec theta - cot theta/cosec^2 theta - cot ^2 theta - 1/sin theta
= cosec theta - cot theta/1 - 1/sin theta
= sin theta(cosec theta - cot theta)-1/sin theta
= 1-cos theta - 1/sin theta
= 1/sin theta - cos theta/sin theta - 1/sin theta
= 1/sin theta - cot theta - cosec theta
= 1/sin theta - (cosec theta + cot theta)
= 1/sin theta - (cosec theta + cot theta) * (cosec theta - cot theta)/cosec theta - cot theta)
= 1/sin theta - 1/(cosec theta - cot theta)
Hope it helps ❤️
here's the answer.....
Given, 1/cosec theta + cot theta - 1/sin theta
It can be written as,
= 1/cosec theta + cot theta * cosec theta - cot theta/cosec theta - cot theta - 1/sin theta
= cosec theta - cot theta/cosec^2 theta - cot ^2 theta - 1/sin theta
= cosec theta - cot theta/1 - 1/sin theta
= sin theta(cosec theta - cot theta)-1/sin theta
= 1-cos theta - 1/sin theta
= 1/sin theta - cos theta/sin theta - 1/sin theta
= 1/sin theta - cot theta - cosec theta
= 1/sin theta - (cosec theta + cot theta)
= 1/sin theta - (cosec theta + cot theta) * (cosec theta - cot theta)/cosec theta - cot theta)
= 1/sin theta - 1/(cosec theta - cot theta)
Hope it helps ❤️
Answered by
6
I hope this helps; )
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