Prove that:
(1 + cot 0 + tan 0) (sin 0 - cos O)/
(seco - cosec )=
sin 2cos2
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Answer:
if (1+cot0 +tan0)(sin0-cos0) / sec0-cosec0 = sin0cos0
SO,
(1 + cos0/sin0 + sin0cos0)(sin0-cos0) / (1/cos0 + 1/sin0)
by taking the LCM and by cutting we get,
LHS=RHS
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