Prove that 1+(cot^2 theta-tan^2 theta) cos^2 theta = cos^2 theta
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{ Math | trig | identities }
sin(theta) = a / c csc(theta) = 1 / sin(theta) = c / a
cos(theta) = b / c sec(theta) = 1 / cos(theta) = c / b
tan(theta) = sin(theta) / cos(theta) = a / b cot(theta) = 1/ tan
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