prove that 1 + Cot ²theta = cosec²theta
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Answer:
cosec^2-cot^2=1
cosec theta=hypotenuse/opposite=ac/ab
cot theta=adjacent/opposite=bc/ab
Step-by-step explanation:
by pythagoreas theorem. (ac)^2=(ab)^2+(bc)^2
taking (ab)^2 on both sides for dividing
(ac)^2/(ab)^2=(ab)^2/(ab)^2+(bc)^2/(ab)^2
[in r.h.s ab^2 and ab^2 are cancelled]
(ac/ab)^2=(1)^2 (bc/ab)^2
then {we consider that ac/ab=cosec theta and bc/ab=cot theta}
therefore (cosec theta)^2=(1)^2+(cot theta)^2
hence proved
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