prove that:- (1+cot Q-cesec Q) (1+tan Q+sec Q) =2
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Answer:
LHS=(1+cot Q-cosec Q)(1+tan Q+secQ)
LHS=(1+cosQ/sinQ-1/sinQ)(1+sinQ/cosQ+1/cosQ)
LHS=(sinQ+cosQ-1/sinQ)(cosQ+sinQ+1/cosQ)
LHS=(sinQ+cosQ)^2-1^2/sinQcosQ
LHS=sinQ^2+cosQ^2+2sinQcosQ-1/sinQcosQ
LHS=1+2sinQcosQ-1/sinQcosQ
LHS=2sinQcosQ/sinQcosQ
LHS=2=RHS
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