Math, asked by adityasingh29, 1 year ago

prove that :(1+cotA+tanA)(sinA-cosA)=sinA.tanA-cotA.cosA

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adityasingh29: but in India all are equal

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Answers

Answered by ggghh76

Answer:

LHS= (1+cotA+tanA)(sinA-cosA)

=sinA+sinAcotA+sinAtanA-cosA-cosAcotA-

cosAtanA

=sinA+sinAcosA/sinA+sinAsinA/cosA-cosA

-cosAcosA/sinA-cosAsinA/cosA

=sinA+cosA+sin^2A/cosA-cosA-

cos^2A/sinA-sinA

=sin^2A/cosA-cos^2A/sinA

=sinA(sinA/cosA)-cosA(cosA/sinA) ----(1)

=1/cosecA(1/cosecA/1/secA)-1/secA(1/secA/

1/cosecA)

=(1/cosec^2A)(secA)-(1/sec^2)(cosecA)

=secA/cosec^2A-cosecA/sec^2A ----(2)

=sinAtanA-cosAcotA ---------------(3)

from (1)

from 2 and 3

=RHS

adityasingh29: but follow each other

adityasingh29: ok

ggghh76: ok

ggghh76: byeeeeee

adityasingh29: in this comment

adityasingh29: byee

akashvs321pah7yq: I dont think this girls is from US

akashvs321pah7yq: Am talking talkin' about ggghh76

adityasingh29: ohh

Answered by mridulapunjabi2003

here is the answer...

hope it helps...^_^

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