Math, asked by piyush49640, 1 year ago

prove that(1+cotthita _cosecthita)(1+tantheta+sectheta)=2

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Answered by Magic55
0
Expanding the same we get 1 + tanθ + secθ+ cotθ + tanθcotθ + secθcotθ - cscθ - cscθtanθ - cscθsecθ  1 + sinθ/cosθ + 1/cosθ + cosθ/sinθ + tanθ * 1/tanθ + 1/sinθ - 1/sinθ - sinθ/cosθ - 1/sinθ * 1/cosθ  1 + 1/sinθcosθ + 1/cosθ + 1 - 1/cosθ - 1/sinθcosθ  =2
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