prove that 1 minus cos theta divided by 1 + cos theta is equal to cosec theta minus cot theta whole square
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Step-by-step explanation:
1-cos Ф/1+cosФ
multiply both upside and downside by 1-cosФ
(1-cos)²/1-cos²Ф
1+cos²Ф+2cosФ/sin²Ф (1-cos²Ф)=sin ²Ф
do partial division:-
1/sin²Ф+cos²Ф/sin²Ф-2cosФ/sin²Ф
cosec²Ф+cot²Ф+cosecФcotФ
(cosecФ+cotФ)²
lhs =rhs
hence proved
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sorry I didn't know this answer
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