prove that 1 minus cos theta over sin theta is equal to sin theta over 1 + cos theta
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(1-cosθ)/sinθ = ((1-cosθ)(1+cosθ))/(sinθ(1+cosθ)) = (1-〖cos〗^2 θ)/(sinθ(1+cosθ))=(〖sin〗^2 θ)/(sinθ(1+cosθ))=sinθ/(1+cosθ)
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