Question

prove that--
1 minus tan theta by 1 plus tan theta equal to cot theta minus 1 by cot theta plus 1​

Answer 1

Step-by-step explanation:

Hope it helps you

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Answer 2

Step-by-step explanation:

LHS:-

$\frac{1 - \tan \alpha }{1 + \tan \alpha } \\ dividing \: both \: the \: numerator \: and \: denominator \: by \: tan \alpha \: we \: get \\ = \frac{ \frac{1}{ \tan \alpha} - \frac{ \tan \alpha }{ \tan \alpha } }{ \frac{1}{ \tan \alpha } + \frac{ \tan\alpha }{ \tan \alpha } } \\ = \frac{ \cot \alpha - 1 }{ \cot \alpha + 1 } ( \frac{1}{ \tan } = \cot)$

=RHS

Hence proved.