Question

prove that (1-omega+omega^2)^7+(1+omega-omega^2)^7=128

Answer 1

Answer:

omega square is equal to one in complex numbers omega square is not equal to 1 . it's cube is equal to one . cube root of unity are 1,ω,ω^2. where 1+ω+ω^2=0,{ω=(-1+i√3)/2, so ω^2=1/ω,and finally ω^3=1.