Question

prove that
1)root 3 is irrational number ​

Answer 1

Answer:

hello

Step-by-step explanation:

while division you'll notice that root 3 neither has a terminating decimal nor  a repeating non-terminating one . hence it is an irrational number.

Answer 2

Answer:

That's very easy!!!

Step-by-step explanation:

Let us suppose that √3 is a rational number.

so, √3 = p/q where q is not equal to 0 and p and q are integers which have no common prime factors other than 1

Now,

√3 = p/q

p = q√3

on squaring both sides,

p² = 3q²

q² = p²/3.....(1.)

p² divided by 3

p also divided by 3

Let p = 3m

on squaring both sides,

p² = 9m²

Now,

from equation (1.)

q² = 9m²/3

q² = 3m²

m² = q²/3.........(2.)

q² divided by 3

q also divided by 3

so, from equation 1st and 2nd

Our supposition is wrong.

√3 is an irrational number.

H.Proved