Math, asked by neyantalama3338, 1 year ago

Prove that [1/sec square a-cos square a+1/cosec square a-sin square a]sin square a cos square a


mohansrinivas15mohan: please put the complete question. u just put only pt. where is =

Answers

Answered by Anonymous
1
The answer of this question will be=1
Answered by Anonymous
0

Consider the provided information.

\sin^2A\cos^2B-\cos^2A\sin^2B=\sin^2A-\sin^2B

Consider the LHS.

\sin^2A\cos^2B-\cos^2A\sin^2B

\sin^2A(1-\sin^2B)-(1-\sin^2A)\sin^2B               (∴\cos^2x=1-\sin^2x)

\sin^2A-\sin^2A\sin^2B-\sin^2B+\sin^2A\sin^2B

\sin^2A-\sin^2B

Hence, proved.

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