prove that 1+secA/secA= sin^2/1-cosA
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Given:-1+secA/SecA=Sin^ 2A/1-CosA
Now from LHS=1/SecA+secA/secA=CosA+1
Now From RHS=Sin^2 A/1-CosA=1-Cos^2 A/1-CosA=(1+CosA)(1-CosA)/1-CosA=CosA+1
LHS=RHS HENCE PROVED
HOPE THIS ANSWER HELPS PLS MARK IT AS THE BRAINLIEST ANSWER
Now from LHS=1/SecA+secA/secA=CosA+1
Now From RHS=Sin^2 A/1-CosA=1-Cos^2 A/1-CosA=(1+CosA)(1-CosA)/1-CosA=CosA+1
LHS=RHS HENCE PROVED
HOPE THIS ANSWER HELPS PLS MARK IT AS THE BRAINLIEST ANSWER
Answered by
6
LHS= 1/sec A+secA/secA=cosA+1
RHS=sin^A/1-cosA=1=1-cosA/1-cosA=(1+cosA)(1-cosA)/1-cosA=cosA+1
lhs=rhs HENCE PROVED
RHS=sin^A/1-cosA=1=1-cosA/1-cosA=(1+cosA)(1-cosA)/1-cosA=cosA+1
lhs=rhs HENCE PROVED
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