Math, asked by hermione12361, 9 months ago

Prove that 1/secA-tanA=1+sinA/cosA

Answers

Answered by sanehasalotra
1

Step-by-step explanation:

hope it helps..........

Attachments:
Answered by sandy1816
2

 \frac{1}{secA- tanA}  \\  \\  =  \frac{1}{secA - tanA}  \times  \frac{secA + tanA}{secA+ tanA}  \\  \\  =  \frac{secA + tanA}{ {sec}^{2}A -  {tan}^{2}  A}  \\  \\  = secA + tanA \\  \\  = secA + tanA \\  \\  =  \frac{1 + sinA}{cosA}

Similar questions