Math, asked by BajWarring, 3 months ago

Prove that

1

SecA-TanA.

Answers

Answered by jitendradhakkarwal

0

Answer:

Given,

secA−tanA

1

−

cosA

1

=

cosA

1

−

secA+tanA

1

or

secA−tanA

1

+

secA+tanA

1

=

cosA

1

+

cosA

1

Here, R.H.S.=

cosA

2

Now,

L.H.S.=

secA−tanA

1

+

secA+tanA

1

=

(secA−tanA)(secA+tanA)

secA+tanA+secA−tanA

=

cosA

2

Thus, L.H.S.=R.H.S.

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