Question

Prove that
1+( secA - tanA) whole square by cosecA(secA- tanA) = 2tanA

Answer 1

Answer:

1 + (sec^2 A - 2secA tanA + tan^2 A) / cosecA ( secA - tanA) = 

(1 + tan^2 A) + sec^2 A - 2secA tanA / cosecA ( secA - tanA) = 

sec^2 A + sec^2 A - 2secAtanA / cosecA ( secA - tanA) = 

2 sec^2 A - 2 secAtanA / cosecA ( secA - tanA) 

2 sec A (secA - tanA) / cosecA ( secA - tanA) 

= 2 sec A / cosecA = 2 tan A

OR SEE THE ATTACHMENT BELOW↓↓

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