Prove that :1+ sin theta/1- Sin theta =( sec theta + tan theta)²
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Step-by-step explanation:
LHS =
1+sinθ
1−sinθ
Multiply and divide by (1−sinθ)
=
1+sinθ
1−sinθ
×
1−sinθ
1−sinθ
=
cos
2
θ
(1−sinθ)
2
=(
cosθ
1−sinθ
)
2
=(secθ−tanθ)
2
=RHS
Hence proved
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