Math, asked by preethigowda571, 3 months ago

prove that √1-sin2A/1+sin2A=tan(Π/4+A

Answers

Answered by Anonymous

0

Answer:

ANSWER

Prove that:

1−sin2A

1+sin2A

=tan(

4

π

+A)

L.H.S

1−sin2A

1+sin2A

=

(cosA−sinA)

2

(sinA+cosA)

2

=

−sinA+cosA

sinA+cosA

=

1−tanA

1+tanA

=tan(

4

π

+A)

Hence, proved.

Answered by Anonymous

0

Answer:

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