prove that √1-sin2A/1+sin2A=tan(Π/4+A
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Answered by
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Answer:
ANSWER
Prove that:
1−sin2A
1+sin2A
=tan(
4
π
+A)
L.H.S
1−sin2A
1+sin2A
=
(cosA−sinA)
2
(sinA+cosA)
2
=
−sinA+cosA
sinA+cosA
=
1−tanA
1+tanA
=tan(
4
π
+A)
Hence, proved.
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