Question

prove that 1-sinA/1+sinA=1+2tanA(tanA-secA)

Answer 1

1-sinA/1+sinA =divide bycosA= 1-cosAtanA/1+cosAtanA ;then write cos in form of sec then you will get secA -tanA/secA+tanA then multiply and divide by secA-tanA by using property you will get answer