Question

the sum of four consecutive integers is 266. what are integer

Answer 1

Let the irst integer be x so 2nd, 3rd and 4th integers are (x+1), (x+2), (x+3)
According to the question
x+ (x+ 1) + ( x + 2) + ( x +3) = 266
So 4x + 6 = 266
So 4x = 266-6
So x = 260/4
So x = 85
x + 1 = 86
x + 2 = 87
x + 3 = 88

Answer 2

Let the first integer be x.
second integer be (x+1)
third integer be (x+2)
fourth integer be (x+3)

BY CONDITION,
x+(x+1)+(x+2)+(x+3) = 266.
=> x + x + 1 + x + 2 + x + 3 = 266
=> 4x+6 = 266.
=> 4x = 266-6 = 260
=> x = 260/4 = 65.

Hence, first integer is 65.
second integer is 66
third integer is 67
fourth integer is 68


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