Math, asked by 9439661973, 11 months ago

the sum of four consecutive integers is 266. what are integer

Answers

Answered by supritinayak7pbae9m

Let the irst integer be x so 2nd, 3rd and 4th integers are (x+1), (x+2), (x+3)
According to the question
x+ (x+ 1) + ( x + 2) + ( x +3) = 266
So 4x + 6 = 266
So 4x = 266-6
So x = 260/4
So x = 85
x + 1 = 86
x + 2 = 87
x + 3 = 88

supritinayak7pbae9m: 65

supritinayak7pbae9m: sorry wrong dtp

supritinayak7pbae9m: answer is 65,66,67 and 68

Answered by Rumi123456789

Let the first integer be x.
second integer be (x+1)
third integer be (x+2)
fourth integer be (x+3)

BY CONDITION,
x+(x+1)+(x+2)+(x+3) = 266.
=> x + x + 1 + x + 2 + x + 3 = 266
=> 4x+6 = 266.
=> 4x = 266-6 = 260
=> x = 260/4 = 65.

Hence, first integer is 65.
second integer is 66
third integer is 67
fourth integer is 68

HOPE YOU UNDERSTAND IT DEAR........!!!!!!!
IF YOU CAN, THEN KINDLY MARK THIS ANSWER AS BRAINLIEST........!!!!!!!

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