Question

Prove that 1_sinA÷1+sinA=(secA_tanA)**2

Answer 1

Step-by-step explanation:

L.H.S

1-sinA/1+sinA

Rationalising the denominator

1-sinA (1-SinA) /1+sinA(1-SinA

(1-SinA)²/ 1² -(Sin²A)

(1-SinA)²/ 1 -(Sin²A)

(1-SinA)² /Cos² A). ........[ 1 -Sin²A = cos²A]

(1-SinA/CosA)²

(1/CosA-SinA/CosA)²

(SecA-tanA)²

L.H S = R H.S

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