Math, asked by parinitayadav202, 5 months ago

prove that √1-sinA/1+sinA=secA-tanA

Answers

Answered by kartikeya327
1

LHS

=√(1 + sin∅)/√(1 - sin∅)

=√(1 + sin∅) × √(1 + sin∅)/√(1 -sin∅)×√(1 +sin∅)

=√(1 + sin∅)²/√(1 -sin²∅)

=(1 + sin∅)/√cos²∅

=(1 + sin∅)/cos∅

=1/cos∅ + sin∅/cos∅

=sec∅ + tan∅

=RHS

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