Math, asked by chetanjnv1600, 8 months ago

Prove that 1-sinA/1+sinA = (secA -tanA)square

Answers

Answered by nrathour769
1

Here is your answer~~

1-sinA/1+sinA

(1-sinA) to multiple and divide---

1+sin^2A-2sinA/cos^2A

 sec^2A+tan^2A-2secA.tanA

(secA-tanA)^2

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