Prove that: (1 – tan^2 A ) + ( 1 + tan^2 A) = 2 sec^2 A.
Answers
Answered by
1
Answer:
Take left hand side of the equation (1+tanA)
2
+(1−tanA)
2
=2sec
2
A.
LHS = (1+tanA)
2
+(1−tanA)
2
=1+tan
2
A+2tanA+1+tan
2
A−2tanA
=2+2tan
2
A
=2(1+tan
2
A)
=2sec
2
A
=RHS
Step-by-step explanation:
Answered by
0
Answer:
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